Can syntactic constructors in Python be overridden?

Can syntactic constructors in Python be overridden?

Couldn't find a way to phrase the title better, feel free to correct.
I'm pretty new to Python, currently experimenting with the language.. I've
noticed that all built-ins types cannot be extended with other members..
I'd like for example to add an each method to the list type, but that
would be impossible. I realize that it's designed that way for efficiency
reasons, and that most of the built-ins types are implemented in C.
Well, one why I found to override this behavior is be defining a new
class, which extends list but otherwise does nothing. Then I can assign
the variable list to that new class, and each time I would like to
instantiate a new list, I'd use the list constructor, like it would have
been used to create the original list type.
class MyList(list):
def each(self, func):
for item in self:
func(item)
list = MyList
my_list = list((1,2,3,4))
my_list.each(lambda x: print(x))
Output:
1
2
3
4
The idea can be generalize of course by defining a method that gets a
built it type and returns a class that extends that type. Further more,
the original list variable can be saved in another variable to keep an
access to it.
Only problem I'm facing right now, is that when you instantiate a list by
it's syntactic form, (i.e. [1,2,3,4]), it will still use the original list
constructor (or does it?). Is there a way to override this behavior? If
the answer is no, do you know of some other way of enabling the user to
extend the built-ins types? (just like javascript allows extending
built-ins prototypes).
I found this limitation of built-ins one of Python's drawbacks, making it
inconsistent with other user-defined types... Overall I really love the
language, and I really dont understand why this limitation is REALLY
necessary.